20x^2+36x=-12x-16

Solution for 20x^2+36x=-12x-16 equation:

20x^2+36x=-12x-16

We move all terms to the left:

20x^2+36x-(-12x-16)=0

We get rid of parentheses

20x^2+36x+12x+16=0

We add all the numbers together, and all the variables

20x^2+48x+16=0

a = 20; b = 48; c = +16;
Δ = b2-4ac
Δ = 482-4·20·16
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-32}{2*20}=\frac{-80}{40}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+32}{2*20}=\frac{-16}{40}
=-2/5
$